LeetCode: 232. Implement Queue using Stacks

题目描述

Implement the following operations of a queue using stacks.

  • push(x) — Push element x to the back of queue.
  • pop() — Removes the element from in front of queue.
  • peek() — Get the front element.
  • empty() — Return whether the queue is empty.

Example:

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MyQueue queue = new MyQueue();

queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false

Notes:

  • You must use only standard operations of a stack — which means only push to top, peek/pop from top, size, and is empty operations are valid.
  • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
  • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

使用stack模拟queue,对于peek和pop操作需要另外一个stack协助完成,原stack进行pop操作的时候另一个stack进行push来保存所有元素。

代码实现

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class MyQueue {
private:
stack<int> _stack;

public:
/** Initialize your data structure here. */
MyQueue() {

}

/** Push element x to the back of queue. */
void push(int x) {
this->_stack.push(x);
}

/** Removes the element from in front of queue and returns that element. */
int pop() {
stack<int> tmp;
assert (!this->_stack.empty());
int popNum = 0;
while (!this->_stack.empty()) {
popNum = this->_stack.top();
this->_stack.pop();
if (!this->_stack.empty()) {
tmp.push(popNum);
}
}
while (!tmp.empty()) {
this->_stack.push(tmp.top());
tmp.pop();
}
return popNum;
}

/** Get the front element. */
int peek() {
stack<int> tmp;
int topNum = 0;
while (!this->_stack.empty()) {
tmp.push(this->_stack.top());
this->_stack.pop();
}
topNum = tmp.top();
while (!tmp.empty()) {
this->push(tmp.top());
tmp.pop();
}
return topNum;
}

/** Returns whether the queue is empty. */
bool empty() {
return this->_stack.empty();
}
};